Pages

Wednesday, August 3, 2011

Time to prove some math

Let ab (10a + b) be the two digits of your age
and cd (10c + d) be the last 2 digits of your cellphone number.

Steps:

1) Multiply your cellphone's last two digits by 2.
          2 x (10c + d) -----> 20c + 2d

2) Add 5.
          20c + 2d + 5

3) Multiply by 50.
          50 x (20c + 2d + 5) -----> 1000c + 100d + 250
          [A/N: If you noticed, the first two terms, 1000c + 100d has become the first two digits of the output.]


4) Add your age.
          1000c + 100d + 250 + (10a + b) -----> 1000c + 100d + 10a + b + 250
          [A/N: Again, the first four terms adds up to become a 4-digit number, the first two (cd) is the last two digits of your cellphone number and the last two (ab) is your age.]


5) Add 365.
          1000c + 100d + 10a + b + 250 + 365 -----> 1000c + 100d + 10a + b + 615

6) Subtract 615.
          1000c + 100d + 10a  + b + 615 - 615 -----> 1000c + 100d + 10a + b

7) The last two numbers are your age and the first two digits are your cellphone's last numbers!
          1000c + 100d + 10a + b ----> cdab [(cd - cellphone's last two digits) (ab - age)]


And there you go, simple math trick where you basically just spin around the numbers and play with them for a bit, but a powerful effect when done correctly as well.

A/N: I'm sorry, I'm just so effin' bored, then I saw this and actually tried it out with the solution I made, and it works :))